Solución al problema 45

Enunciado del problema 45

$$\begin{array}{ccc}11_{(k}& =& 1+k\\ 1331_{(k}& =& 1+3k+3k^2+k^3=(1+k{)}^3\\ \sum _{k=5}^{k=49}\frac{11_{(k}}{\sqrt[3]{1331_{(k}}}& =& \sum _{k=5}^{k=49}\frac{1+k}{1+k}=\sum _{k=5}^{k=49}1=44\end{array}$$